Factoring
over
In other words, we shall express
as a product of
irreducible polynomials having coeficients in
.
This is, in fact, very easy. The complex roots of
are precisely the
roots of unity: those numbers
for
which
To determine these, recall that any complex number
may
be written in its polar decomposition,
,
where
and
are it's
``polar coordinates''. (Moreover, if
then
these coordinates are unique.) Then
implies
, which in turn implies
(so
since
) and
.
Substituting these into
, we find
that
must be equal to one of the following numbers:
In fact, this sequence is periodic, so only
the first
terms are distinct and after that the
numbers start repeating themselves.
We summarize this as the following result.
Lemma 2.10.5
The complex roots of
are
These may be visualized as follows. In general, plot the
complex number
at the point
in the
-plane. (Sometimes this
way of plotting complex numbers is called the
Gaussian plane.) The
roots of
are equally spaced points on the unit circle,
starting at
.
In fact,
is the factorization into irreducibles
opver
. In other words, factoring
over
amounts geometrically to
subdividing the circle into
equal parts.
Remark 2.10.6
The ancient Greeks asked for which
is it possible to
subdivide the circle into
equal parts
using only a ruler and compass. This, and its connection
with factoring polynomials, is discussed
in further detail in chapter 22 of Schroeder [Sch].
david joyner
2008-04-20