Integral powers mod $ n$

In calculus, you learn to solve (or at least find approximate solutions to) equations of the form $ y=a^x$ . Solving for $ x$ in terms of $ y$ incolves using the logarithm to base $ a$ .

We want to do something analogous here. One difference here is that, because the integers are discrete, there are no approximate solutions!

Definition 1.8.1   Let $ a\geq 1,n>1$ be relatively prime integers. We say that $ a$ has order $ k$ modulo $ n$ is $ k$ if $ k$ is the smallest positive integer satisfying $ a^k\equiv 1  ({\rm mod} n)$ . The order is denoted $ {\rm ord}_n(a)$ .

For example, the order of $ a=2$ modulo $ n=7$ is $ k=3$ since $ 2^3\equiv 1 ({\rm mod} 7)$ .

One way to think about the material in this section is it is a study of properties of the order function. The order of an integer is not ``easy'' to find in the sense that if $ n$ is a large integer then there is no known ``efficient'' algorithm for determining $ {\rm ord}_n(a)$ [BS].



Subsections

david joyner 2008-04-20