Application: Divisibility criteria revisited

Let

$\displaystyle a=a_k10^k+...a_1 10+a_0,
$

where $ 0\leq a_i\leq 9$ are the digits. The following congruence conditions generalize some of the criteria given in §1.7.1.

mod 2
: $ a \equiv a_0 ({\rm mod} 2)$ .

mod 3
: $ a \equiv (a_0+a_1+...+a_k) ({\rm mod} 3)$ .

mod 4
: $ a \equiv (a_0+a_1 10) ({\rm mod} 4)$ .

mod 5
: $ a \equiv a_0 ({\rm mod} 5)$ .

mod 8
: $ a \equiv (a_0+10a_1+100a_2) ({\rm mod} 8)$ .

mod 9
: $ a \equiv (a_0+a_1+...+a_k) ({\rm mod} 9)$ .

For example, $ 11116\equiv 1  ({\rm mod} 9)$ .

mod 10
: $ a \equiv a_0 ({\rm mod} 10)$ .

There are also conditions for $ 7$ , $ 11$ , and $ 13$ but they are left as exercises.



david joyner 2008-04-20