Determinants

The determinant of a matrix $ A$ , denoted $ \det(A)$ , is only defined when $ A$ is a square matrix, i.e., the number of rows is equal to the number of columns. If $ A$ is an $ n\times n$ matrix then $ A$ may be regarded as a function of $ F^n$ , sending vectors to points.

If $ F=\mathbb{R}$ then it turns out the matrix $ A$ , regarded as a function $ A:\mathbb{R}^n\rightarrow \mathbb{R}^n$ , will send the unit hypercube $ [0,1]\times ...\times [0,1]$ ($ n$ times) in $ \mathbb{R}^n$ to a parallelepiped (the $ n$ -dimensional analog of a parallelogram). It is known that the absolute value of the determinant of $ A$ measures the volume of that parallelpiped. For example, \begin{displaymath}A=\left(
\begin{array}{cc}
2&1\\
1&2
\end{array}
\right)\end{displaymath} sends the vertices of the unit square $ [0,1]\times [0,1]=\{(x,y) \vert 0\leq x\leq 1, 0\leq y\leq 1\}$ to the points $ (0,0)$ , $ (2,1)$ , $ (1,2)$ , $ (3,3)$ . These points bound a parallelogram having volume $ \det(A)=3$ .

If $ m=n=2$ the determinant is easy to define:

\begin{displaymath}
\det\left(
\begin{array}{cc}
a&b\\
c&d
\end{array}
\right)=ad-bc.
\end{displaymath}

The easiest constructive way to define the determinant of an arbitrary $ n\times n$ matrix $ A=(a_{ij})$ is to use the Laplace cofactor expansion (along the $ i^{th}$ row): for any $ 1\leq i\leq n$ , we have

$\displaystyle \det(A)=\sum_{j=1}^n (-1)^{i+j}\det(A_{ij}),$ (5.2)

where $ A_{ij}$ is the $ (n-1)\times (n-1)$ `submatrix of $ A$ ' obtained by omitting all the entries in the $ i^{th}$ row or the $ j^{th}$ column. The matrix $ A_{ij}$ is called the $ (i,j)$ -minor of $ A$ and $ (-1)^{i+j}\det(A_{ij})$ is called the $ (i,j)$ -cofactor.

The determinant has many remarkable properties. For example,

For a proof, see any text on linear algebra (e.g., [JN]).

A square matrix $ A$ is singular if $ \det(A)=0$ . Otherwise, $ A$ is called non-singular or invertible.

Example 5.5.1   Taking $ i=2$ ,

\begin{displaymath}
\begin{array}{c}
\det\left(
\begin{array}{ccc}
1&2&3\ 
...
...\right)\\
=(-4)(18-24)+(5)(9-21)+(-6)(8-14)=0.
\end{array}
\end{displaymath}

This implies $ A$ is singular. Indeed, the parallelepiped generated by $ (1, 2, 3)$ , $ (4,5,6)$ , $ (7,8,9)$ , must be flat ($ 2$ -dimensional, hence have 0 volume) since $ (4,5,6)=(1,2,3)+(1,1,1)$ and $ (7,8,9)=(1,2,3)+2(1,1,1)$ .

An important fact about singular matrices, and one that we will use later, is the following.

Lemma 5.5.2   Suppose $ A$ is an $ n\times n$ matrix with entries in $ F$ . The following are equivalent:

For a proof, see any text on linear algebra.

We end this section with one last key property of determinants.

Lemma 5.5.3   If $ A,B$ are any two $ n\times n$ matrices having entries in $ F$ then $ \det(AB)=\det(A)\det(B)$ .

More details on all this material can be found in any text book on linear algebra.



david joyner 2008-04-20