Hamming codes

The $ [7,4,3]$ -Hamming code over $ GF(2)$ having generator matrix

\begin{displaymath}
\left(
\begin{array}{ccccccc}
1& 0& 0& 0& 0& 1& 1\\
0& 1& 0...
...
0& 0& 1& 0& 1& 1& 0\\
0& 0& 0& 1& 1& 1& 1
\end{array}\right)
\end{displaymath}

is obtained by typing

C:=HammingCode(GF(2),3);
C;
G:=GeneratorMatrix(C);
G;
Encoding a message $ w$ using $ G$ , is simply the map $ w\longmapsto wG$ . Type
W:=InformationSpace(C);
Cwords:=<w*G : w in W>;
Cwords;
#Cwords;

From this, you see all the codewords of C and how many there are.

To get the parity check matrix, type H:=ParityCheckMatrix(C); H; To see if a vector in $ \mathbb{F}^7$ is a codeword, simply compute $ Hv$ and check if it is zero or not. Here's a MAGMA example 3.3:

V:=AmbientSpace(C);
v:=V![1,0,0,0,0,0,0];
v*Transpose(H);

Since this last vector is non-zero, $ v$ is not a codeword. If it was a vector received in transmission (with at least one error) then to decode it, hence to find the most likely codeword sent, type

Decode(C,v);

Exercise 3.15.2 (a)   For the parity check matrix $ H$ of the binary Hamming code of length $ 2^3-1=7$ , verify $ Hc=0$ for three or four codewords c. Decode $ (1,1,0,0,0,0,0)$ .

(b) Find a parity check matrix of the $ 3$ -ary Hamming code of length $ (3^3-1)/(3-1)=13$ . Verify $ Hc=0$ for three or four codewords $ c$ . Decode $ (1,2,1,2,1,2,1,2,1,2,1,2,1)$ .

To get the dimension of the code, type Dimension(C); To get its minimum distance, type MinimumDistance(C);

Exercise 3.15.3   Find the dimension and minimum distance of

(a) the binary Hamming code of length $ 15$ ,

(b) the 3-ary Hamming code of length $ 13$ .



david joyner 2008-04-20